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Oracle 1z1-071 certification exam, also known as the Oracle Database SQL exam, is designed to test individuals' knowledge and skills in SQL programming, data modeling, and database management. Oracle Database SQL certification is intended for individuals who want to demonstrate their proficiency in working with Oracle databases and SQL programming. 1z0-071 Exam is recognized worldwide as a benchmark for Oracle SQL expertise and is highly valued by employers.

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Oracle Database SQL Sample Questions (Q121-Q126):

NEW QUESTION # 121
Examine the structure of the BOOKS_TRANSACTIONS table:

Examine the SQL statement:

Which statement is true about the outcome?

A. It displays details only for members who have borrowed before today with RM as TRANSACTION_TYPE.
B. It displays details for only members A101 and A102 who have borrowed before today with RM TRANSACTION_TYPE.
C. It displays details for members who have borrowed before today with RM as TRANSACTION_TYPE and the details for members A101 or A102.
D. It displays details for members who have borrowed before today's date with either RM as TRANSACTION_TYPE or MEMBER_ID as A101 and A102.

Answer: C

NEW QUESTION # 122
Which two tasks require subqueries?

A. Display the total number of products supplied by supplier 102 which have a product status of obsolete.
B. Display suppliers whose PROD_LIST_PRICE is less than 1000.
C. Display the number of products whose PROD_LIST_PRICE is more than the average PROD_LIST_PRICE.
D. Display products whose PROD_MIN_PRICE is more than the average PROD_LIST_PRICE of all products, and whose status is orderable.
E. Display the minimum PROD_LIST_PRICE for each product status.

Answer: C,D

Explanation:
C: True. To display the number of products whose PROD_LIST_PRICE is more than the average PROD_LIST_PRICE, you would need to use a subquery to first calculate the average PROD_LIST_PRICE and then use that result to compare each product's list price to the average.
E: True. Displaying products whose PROD_MIN_PRICE is more than the average PROD_LIST_PRICE of all products and whose status is orderable would require a subquery. The subquery would be used to determine the average PROD_LIST_PRICE, and then this average would be used in the outer query to filter the products accordingly.
Subqueries are necessary when the computation of a value relies on an aggregate or a result that must be obtained separately from the main query, and cannot be derived in a single level of query execution.
Reference:
Oracle's SQL documentation provides guidelines for using subqueries in scenarios where an inner query's result is needed to complete the processing of an outer query.

NEW QUESTION # 123
You need to produce a report where each customer's credit limit has been incremented by $1000. In the output, the customer's last name should have the heading Nameand the incremented credit limit should be labeled New Credit Limit. The column headings should have only the first letter of each word in uppercase.
Which statement would accomplish this requirement?

A. SELECT cust_last_name AS Name, cust_credit_limit + 1000
AS New Credit Limit
FROM customers;
B. SELECT cust_last_name AS Name, cust_credit_limit + 1000
"New Credit Limit"
FROM customers;
C. SELECT INITCAP (cust_last_name) "Name", cust_credit_limit + 1000
INITCAP ("NEW CREDIT LIMIT")
FROM customers;
D. SELECT cust_last_name AS "Name", cust_credit_limit + 1000
AS "New Credit Limit"
FROM customers;

Answer: D

NEW QUESTION # 124
Examine the structure of the BOOKS_TRANSACTIONS table:
NameNull?Type
------------------------------------------------------------
TRANSACTION_IDNOT NULLVARCHAR2 (6)
BORROWED_DATEVARCHAR2 (50)
DUE_DATEDATE
BOOK_IDDATE
MEMBER_IDVARCHAR2 (6)
You want to display the member IDs, due date, and late fee as $2 for all transactions.
Which SQL statement must you execute?

A. SELECT member_id AS "MEMBER ID", due_date AS "DUE DATE", '$2' AS "LATE FEE" FROM BOOKS_TRANSACTIONS;
B. SELECT member_id 'MEMBER ID', due_date 'DUE DATE', '$2 AS LATE FEE' FROM BOOKS_TRANSACTIONS;
C. SELECT member_id AS "MEMBER ID", due_date AS "DUE DATE", $2 AS "LATE FEE" FROM BOOKS_TRANSACTIONS;
D. SELECT member_id AS MEMBER_ID, due_date AS DUE_DATE, $2 AS LATE_FEE
FROM BOOKS_TRANSACTIONS;

Answer: A

NEW QUESTION # 125
Examine the structure of the INVOICEtable.

Which two SQL statements would execute successfully?

A. SELECT inv_no, NVL2(inv_date, sysdate-inv_date, sysdate)
FROM invoice;
B. SELECT inv_no, NVL2(inv_date, 'Pending', 'Incomplete')
FROM invoice;
C. SELECT inv_no, NVL2(inv_amt, inv_amt*.25, 'Not Available')
FROM invoice;
D. SELECT inv_no, NVL2(inv_amt, inv_date, 'Not Available')
FROM invoice;

Answer: A,B

NEW QUESTION # 126
......

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